IFTTT Do Button 1 per day limit

[gudamor]

I think you’d want aggregation to be set to:

‘nonzero’ : lambda x: 1 if any([i!=0 for i in x]) else 0 # 1 iff any non-0 datapts

Documentation of aggregation methods would be nice

Great point, @drmaciver, and nice work digging up the answer from Akratics Anonymous, @chelsea UPDATE 2018: The following table gives the aggday functions. They take the list x of raw datapoints on a given day and return the aggregated datapoint that is plotted and counts toward the Beeminder goal. In the actual Python code this is a hash of lambda functions. And np is NumPy. UPDATE 2019: I added cap1 and made it pseudocode instead of strictly Python. last : x[-1] # only the most recent…